26.27 取Unicode字符串的长整型值(little-endian序)

Q:

下面这段Python3代码显示Unicode字符串"www.baidu.com"前16字节的长整数形式，2 个长整数，little-endian序:

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x = 'www.baidu.com' x = "".join([c+'\0' for c in x]).encode( 'latin-1' ).hex() y = x[:16] ''.join(map(str.add, y[-2::-2], y[-1::-2])) y = x[16:32] ''.join(map(str.add, y[-2::-2], y[-1::-2]))

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'002e007700770077' '0064006900610062'

我只会这么矬的办法，不知更好的办法是啥？

A: bluerust 2020-03-07

Python3

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import struct

x = "www.baidu.com" x = bytes( x, encoding='utf-16' )[2:] [hex(struct.unpack( "<Q", x[i:i+8] )[0]) for i in range(0 ,len(x)//8*8, 8)]

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['0x2e007700770077', '0x64006900610062', '0x6f0063002e0075']

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import hexdump

x = "www.baidu.com" x = bytes( x, encoding='utf-16' )[2:] ['0x' + ''.join(map(str.add, y[-2::-2], y[-1::-2])) for y in hexdump.dump( x, size=16, sep=',' ).split( ',' )]

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import hexdump

x = "www.baidu.com" x = bytes( x, encoding='utf-16' )[2:] ['0x' + ''.join(map(str.add, y[-2::-2], y[-1::-2])) for y in hexdump.dump( x, size=16 ).split()]

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['0x002E007700770077', '0x0064006900610062', '0x006F0063002E0075', '0x006D']